Question

solve this question​

Answer 1

$y = \sqrt{ 6 + \sqrt{6 + \sqrt{6 + \sqrt{ 6 + ...... \infty } } } } \\ {y}^{2} = 6 + y \\ {y}^{2} - y - 6 = 0 \\ {y}^{2} - 3y + 2y - 6 = 0 \\ y(y - 3) + 2(y - 3) = 0 \\ (y + 2)(y - 3) = 0 \\ y = - 2 \: not \: possible \: \: \: \: y = 3$