Question

solve this question and it's for 3marks

Answer 1

heres the answer hope this helps

Answer 2

$a = \sqrt{2} \\ b = 1 \\ c = \sqrt{2} \\ x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac } }{2a} \\ = \frac{ - 1 + - \sqrt{1 - 8} }{2 \sqrt{2} } \\ = \frac{ - 1 + - \sqrt{ - 7} }{2 \sqrt{2} } = \frac{ - 1 + - i \sqrt{7} }{2 \sqrt{2 } } \\ x = \frac{ - 1 + i \sqrt{7} }{2 \sqrt{2} } and \frac{ - 1 - i \sqrt{7} }{2 \sqrt{2} }$