Question

solve this question....and no spamming bcoz its imp for me right now

Answer 1

Note: Here I am writing theta as A.

(1)

Cos A tan A

$= \ \textgreater \ cos A * \frac{sin A}{cosA}$

= > sin A




(2)

sin A cot A

$= \ \textgreater \ sin A * \frac{cos A}{sinA}$

= > cos A



(3)

$Given : \frac{sin^2A}{cosA} + cos A$

$= \ \textgreater \ \frac{sin^2 A + cos^2A}{cosA}$

We know that sin^2 theta + cos^2 theta = 1

$= \ \textgreater \ \frac{1}{cosA}$





Hope this helps!

Answer 2

26 - Prove the following:


(i) cos Ф × tan Ф = sin Ф

Solution:- 

LHS

___________________________
|Tan Ф = $\frac{Sin}{cos}$ |
____________________________

⇒ cosФ × tanФ

⇒ cosФ ×$\frac{sin}{cos}$

⇒ sinФ

-----------------

SinФ = sinФ
LHS = RHS

=======================================


(ii)  sinФ × cotФ = cosФ

Solution:-

LHS
___________________________
| CotФ = $\frac{cos}{sin}$ |
___________________________

⇒ sinФ × cotФ

⇒ sinФ ×$\frac{cos}{sin}$ 

⇒ CosФ

---------------

CosФ = cosФ

LHS = RHS

============================

(iii) $\frac{sin^2}{cos} + cos = \frac{1}{cos}$

Solution :-

LHS

$\frac{sin^2 + cos^2 }{cos}$

____________________________
|As we know that sin²Ф + cos²Ф = 1 |
_____________________________

$\frac{sin^2 + cos^2}{cos}$

⇒$\frac{1}{cos}$

--------------------

1/cosФ = 1/cosФ

LHS = RHS



i hope this will help you



-by ABHAY