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Areas related to Circles chapter
Class 10
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Area subtended at P= r^2/2. P
Area subtended at Q = r^2/2. Q
Area subtended at R = r^2/2. R
total area subtended
= r^2/2. ( P + Q + R)
AS P + Q + R = 180 DEGREE OR pie radian
So
r^2/2. ( pie)
put r = 14
14× 14/2. ( 22/7)
308 cm^2
NOTE: Agar yae answer delete hua phir sae "Sharma Shiv am" tho gunda dardi myujha bahut aati hae,
Area subtended at Q = r^2/2. Q
Area subtended at R = r^2/2. R
total area subtended
= r^2/2. ( P + Q + R)
AS P + Q + R = 180 DEGREE OR pie radian
So
r^2/2. ( pie)
put r = 14
14× 14/2. ( 22/7)
308 cm^2
NOTE: Agar yae answer delete hua phir sae "Sharma Shiv am" tho gunda dardi myujha bahut aati hae,
Answered by
6
Answer:
308 cm²
Step-by-step explanation:
Given, radii = 14 cm.
Area of shaded region = Sum of areas of three sectors.
= (∠P/360) * πr² + (∠Q/360) * πr² + (∠R/360) * πr²
= πr²/360°[∠P + ∠Q + ∠R]
= πr²/360[180°] {Sum of angles of a triangle = 180°}
= πr²/2
= 22 * 14²/14
= 4312/14
= 308 cm²
Therefore, Area of shaded region = 308 cm².
Hope it helps!
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