Question

Solve this question came in jee mains ......

Answer 1

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Let the x gram gas is mixed

Mole of ethane =
$\frac{x}{30}$
Mole of hydrogen = x/2

mole fraction of hydrogen =
$\frac{ \frac{x}{2} }{ \frac{x}{2} + \frac{x}{30} } \\ = \frac{15}{16}$


= mole fraction of hydrogen

= 15 : 16


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Answer 2

$\underline{\underline{\Huge\mathfrak{Answer ;}}}$

Let the value of gram mixed be y.

Now ,

Ethane's Mole = y/30
Hydrogen's Mole = y/2

Now ,
Hydrogen's Mole Fraction ;-

$= > \frac{\frac{y}{2} }{ \frac{y}{2} + \frac{y}{30} } = \frac{15}{16}$

In Ratio ;- 15:16

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