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find the smallest 4 digit number which when divided by 17 and 13 leaves a remainder of 7 in each case
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HEY MATE HERE'S UR ANSWER
Let us first find the LCM of 16 and 18. For that we factorize
Let us first find the LCM of 16 and 18. For that we factorize16 = 2x2x2x2
Let us first find the LCM of 16 and 18. For that we factorize16 = 2x2x2x218 = 2x3x3
Let us first find the LCM of 16 and 18. For that we factorize16 = 2x2x2x218 = 2x3x3So the LCM is 2^4*3^2 = 16*9= 144. Next multiply 144 by 7 to get 144x7=1008. To that add 8 to get 1008+8 = 1016.
Let us first find the LCM of 16 and 18. For that we factorize16 = 2x2x2x218 = 2x3x3So the LCM is 2^4*3^2 = 16*9= 144. Next multiply 144 by 7 to get 144x7=1008. To that add 8 to get 1008+8 = 1016. 1016/16 = 63 as quotient and 8 as remainder.
Let us first find the LCM of 16 and 18. For that we factorize16 = 2x2x2x218 = 2x3x3So the LCM is 2^4*3^2 = 16*9= 144. Next multiply 144 by 7 to get 144x7=1008. To that add 8 to get 1008+8 = 1016. 1016/16 = 63 as quotient and 8 as remainder.1016/18 = 56 as quotient and 8 as remainder. Correct.
Let us first find the LCM of 16 and 18. For that we factorize16 = 2x2x2x218 = 2x3x3So the LCM is 2^4*3^2 = 16*9= 144. Next multiply 144 by 7 to get 144x7=1008. To that add 8 to get 1008+8 = 1016. 1016/16 = 63 as quotient and 8 as remainder.1016/18 = 56 as quotient and 8 as remainder. Correct.Hence the number is 1016.
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wrong your answer this question answer is 1112