Question

solve this question frndzzz,........​

Answer 1

$\huge\bigstar\underline\pink{Answer}$

★ for h = 90m

→ distance covered in 3sec =

S = $\frac{1}{2}$at²

=> S = $\frac{1}{2}$×10×3×3

= 45m

⚫ Remaning distance = (90-45) = 45m

★ since, Bird is in rare medium and observe is in denser medium

★ For observer d(apparent ) = d(actual ) × μ

=>. d(apparent ) = 45 × 4/3 = 60m

$\boxed{option\:2\:is\:correct}$

Happy to help!

☺️

Answer 2

Answer:

Note:- check this attachment.!