Question

Solve this question from algebra, and verify the answer.​

Answer 1

GIVEN :-

• a = 1
• b = -1
• c = -2

TO FIND :-

• Multiply the Algebraic Expression.
• Verify the answer.

SOLUTION :-

➬( -5/14 abc ) (7/10 a²b²c²)

➬ ( -5/14 × 7/10 ) ( abc × a²b²c² )

➬ -1/4 a³b³c³ = R.H.S

VERIFICATION :-

➬ L.H.S = ( -5/14 abc ) (7/10 a²b²c²)

➬ [-5/14 × 1 × (-1)× (-2)] [7/10 × (1)² × (-1)² × (-2)²]

➬ [-5/14 × 2] [7/10 × 1 × 1 × 4]

➬ [-5/7] [14/5]

➬ -5/7 × 14/5

➬ -2 ---------------------(1)

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➬ R.H.S = -1/2 a³b³c³

➬ [-1/4 × (1)³ × (-1)³ × (-2)³]

➬ [-1/4 × 8]

➬ -2 --------------------(2)

From Equation (1) and (2)

➬ L.H.S = R.H.S

HENCE VERIFIED ✔

Answer 2

$\large{\red{\underline{\underline{\bold{Given:-}}}}}$

• Multiply -5 × abc/14 by 7 × a²b²c²/10 when the value of a= 1,b= -1,c= -2

$\large{\blue{\underline{\underline{\bold{To Find:-}}}}}$

• The value of a ,b and c when they are given as 1,-1,-2

$\large{\green{\underline{\underline{\bold{Solution:-}}}}}$

$\rightarrow$ Question -5 × abc/14 by 7 × a²b²c²/10

$\rightarrow$ The value of a= 1,b= -1,c= -2

$\rightarrow$ -5 × abc / 14 by 7 × a²b²c² / 10

• Substitute the value of a ,b and c in the equation

$\rightarrow$ -5 × (1)(-1)(-2)/14 / 7× (1)²(-1)²(-2)²/10

$\rightarrow$ -5 × 2 / 14 / 7 × 4 /10

$\rightarrow$ -10 /14 × 28 / 10

$\rightarrow$ -5/7 × 14/5

$\rightarrow$ -2

$\mathbb\pink{VERIFICATION}$

$\rightarrow$ -5 × abc /14 / 7 × a²b²c² / 10

$\rightarrow$ -5/14 × 7/10 (abc × a²b²c²)

$\rightarrow$ Let equation be -1/4 a³b³c³

• Another equation value is -2 ( LHS )

$\rightarrow$ -1/4 × (1)³(-1)³(-2)³

$\rightarrow$ -1/4 × 8

$\rightarrow$ -2

• LHS = RHS
• -2 = -2

Hence verified ✓✓✓✓