solve this question guys
it's easy but critical
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NETWORK ERROR.........
SOLLY YL!!
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Step-by-step explanation:
lets the four no in AP are
a-3d,a-d,a+d,a+3d
where a is first term and d is common difference
by given conditions
a-3d+a-d+a+d+a+3d=28
4a=28
a=7
now square of numbers and add we get
(a-3d)²+(a-d)²+(a+d)²+(a+3d)12
a²+9d²-6ad+a²+d²-2ad+a²+9d²+6ad+a²+d²+2ad =216
plz sovle further
thank you
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