Math, asked by Shruti451, 1 year ago

solve this question I mark you as brainliest

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Answered by TheTitanium
1
length of wire is 108 cm.
2πr/2+2r= 108cm
πr+2r=108cm
22/7+2×r=108cm
3r=108×7/22=34.36
r=34.36/3=11.45cm
therefore, radius=11.45cm
area enclosed= 1/2×πr^2
=1/2×22/7×11.45×11.45
=206.01cm^2
hope this helps you.

TheTitanium: please mark my answer as brainliest.
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