Question

Solve this question immediate answers required

Answer 1

given cosx = t    0 < t < 1
⇒  cosx is positive 

now cosx = t = Base/ hypotense

consider a triangle with base = t  and hypo. = 1
 therefore perpendicular = √1-t²

now sinx = perp. / hypo =  √1-t²/1

and tanx = √1-t² / t

but A/Q  x ∉ 1st quadrant and cosx too positive therefore x∈ 4th quadrant

 and sinx = -√1-t²/1   and tanx = -√1-t²/t

hope u'll get it if doubt then ask........