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Let us assume that √x and √y are irrational no.
⇒√x+√y = a/b where '' a and b'' are integers , b ≠0
⇒ √x = a/b-√y -----(1)
now squaring both side we get
⇒ x = ( a/b -√y )² = a²/b² +y -2ab√y
on solving we get
2a/b√y = a²/b²+y -x
⇒ on solving the equation we get
√y = xb²+a²-b²y/2ab
Irrational = Rational
Thus it is not possible ,so our assumption is wrong
Hence √x+√y is irrational.
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Let assume x+√y be a rational number
Then x+√y=p/q
√y= p/q-x
Therefore √y is a rational number
But in question √y is irrational
Hence, x+√y is irrational
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