solve this question it is from maths class 9
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add both the equation
you will get
A+2B +C = 238
A+B+C +B = 238
180+ B = 238
B = 238-180= 58
A+B = 108
A+ 58 = 108
A = 50
B + C = 130
58 + C = 130
C = 72
you will get
A+2B +C = 238
A+B+C +B = 238
180+ B = 238
B = 238-180= 58
A+B = 108
A+ 58 = 108
A = 50
B + C = 130
58 + C = 130
C = 72
Cinderalla34:
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Answered by
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A + B = 108. 1
B + C = 130. 2
And we know it's a triangle so
A + B + C = 180. 3
Add 1 and 2 and subtract it with 3
A + 2B + C - ( A + B + C ) = 108 + 130 -180
B = 58.
Put in equation 1 and 2
A = 50
C = 72.
So this was the answer to your question
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