Question

Solve this question - k = whole square (a-b ÷ a+b) where k=36 and a=3

Answer 1

$k = (a - b \div a + b) {}^{2} \\ 36 = {(3 - b \div 3 + b)}^{2} \\ 6 = (3 - b) \div (3 + b) \\ 18 + 6b = 3 - b \\ 7b = - 15 \\ b = - 15 \div 7$
b=-15/7

Answer 2

Answer:

$k = (a - b \div a + b) {}^{2} \\ 36 = {(3 - b \div 3 + b)}^{2} \\ 6 = (3 - b) \div (3 + b) \\ 18 + 6b = 3 - b \\ 7b = - 15 \\ b = - 15 \div 7$

$\bf b = \dfrac { -15 } { 7 }$