Question

solve this question...
maths class 10​

Answer 1

Answer:

The answer has been given in above attachment

HOPE SO THIS MAY HELP U

Answer 2

||✪✪ CORRECT QUESTION ✪✪||

Prove that :- (sin A-cos A+1)/(sin A+cosA-1)=1/(sec A-tan A)

|| ✰✰ ANSWER ✰✰ ||

(sin A-cos A+1)/(sin A+cosA-1) = 1/(sec A-tan A)

In L.H.S. divide above and below by cosA we get,

(sinA/cosA-cosA/cosA+1/cosA)/(sinA/cosA+cosA/cosA-1/cosA)

Now, putting sinA/cosA = TanA and 1/cosA = SecA ,

→ (tan A-1+secA)/(tan A+1-sec A)

→ (tan A-1+secA)/(1-sec A+tan A)

Now , Putting 1 = sec²A - tan²A = (sec A+tanA)(secA-tanA) in Denominator , we get,

→ (sec A+tan A-1)/[(sec A+tan A)(sec A-tan A)-(sec A-tan A)]

Taking (secA - TanA) common From Denominator now,

→ (sec A+tan A-1)/(sec A-tan A)(sec A+tan A-1)

→ 1/(sec A-tan A)

✪✪ Hence Proved ✪✪