Question

sum of 4 conservative integers is 266 what are those integers​

Answer 1

Step-by-step explanation:

x+x+1+x+2+x+3 = 266

4x+6=266

4x=266-6

4x=260

x=260/4=130/2=65

x=65

Answer 2

$\huge\mathbb{SOLUTION:-}$

$\sf\underline{\pink{\:\:\:\:\:\:\:Given:-\:\:\:\:\:\:\:}}$

$\sf \bullet let\:the\: integers\:be\\ \sf:\implies x,\:x+1,\:x+2\:,x+3$

Their sum is 266

$\sf:\implies x+x+1+x+2+x+3=266\\ \\ \sf:\implies 4x+6=266\\ \\ \sf:\implies 4x=266-6\\ \\ \sf:\implies 4x=260\\ \\ \sf:\implies x=\cancel{\dfrac{260}{4}}\\ \\ \sf:\implies x= 65$

The numbers is

$\sf\bullet x=65\\ \\ \sf\bullet x+1\\ \sf:\implies 65+1=66\\ \\ \sf\bullet x+2\\ \sf:\implies 65+2=67\\ \\ \sf\bullet x+3\\ \sf:\implies 65+3= 68$

The four consecutive integer is

$\boxed{\sf{65,\:66,\:67\:,68}}$