solve this question no. 8 sub part 2 factorisation
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Solution :
( ax + by )² + ( bx - ay )²
= (ax)² + 2abxy + (by)²+(bx)²-2abxy+(ay)²
= a²x² + b²y² + b²x² + a²y²
= a²( x² + y² ) + b²( y² + x² )
= ( x² + y² )( a² + b² )
••••
( ax + by )² + ( bx - ay )²
= (ax)² + 2abxy + (by)²+(bx)²-2abxy+(ay)²
= a²x² + b²y² + b²x² + a²y²
= a²( x² + y² ) + b²( y² + x² )
= ( x² + y² )( a² + b² )
••••
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