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Answer 1

Step-by-step explanation:

GIVEN:-

Sin θ + cos ec θ =√3

TO PROVE:-

Sin ^2 θ + cos ec^2 θ = 1

STEPS:-

$\sinθ + \frac{1}{ \sinθ} = 2$

SQUARING ON BOTH SIDES :-

$(\sinθ + \frac{1}{ \sinθ } ) {}^{2} = 4</p><p>$

$\sin {}^{2} θ + \frac{1}{ \sin{}^{2} θ } + 2( \sinθ)( \frac{1}{ \sinθ} ) = 4$

$\sin {}^{2} θ + \frac{1}{ \sin {}^{2} θ} + 2 = 4$

$\sin{}^{2} θ + \frac{1}{ \sin {}^{2}θ } = 2$

$answer = \sin{}^{2} θ + \cosec {}^{2}θ = 2 )$

Answer 2

Step-by-step explanation:

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