Question

solve this question of maths 10 class​

Answer 1

Answer:

p(x)=2x^4-3x^3-3x^2+6x-2=0

its two zeroes are ✓2 & -✓2

[x-✓2] [x-(-✓2)]

(x)^2 - (✓2)^2

x^2-2 is the factor of p(x)

p(x)=2x^4-3x^3-3x^2+6x-2/x^2-2

=2x^2-3x+1

for other zeroes

2x^2-3x+1=0

2x^2-2x-x+1=0

2x(x-1) -1(x-1)=0

(x-1) (2x-1) =0

x= 1 and 1/2

Hence all the zeroes of p(x) =✓2, -✓2, 1, 1/2

Answer 2

Answer: Zeroes are √2, -√2, ½, 1.

Hope it works...............................™✌️✌️