Math, asked by qqqqqqppppppqpqpqpqp, 1 year ago

Solve this question of maths
Question no.9 part 2nd

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Answered by TheLifeRacer
2
Hey !!!

Q. no 9 ,part 2nd

Solution :-

From LHS

tan²x /secx - 1

sin²x /cos²x
--------------------
(1/cosx - 1 )²

sin²x /cos²x
---------------------
(1 - cosx )²/cos²x

sin²x /(1 - cosx )²

( 1 - cos²x ) / (1 - cosx)²

(1 - cosx ) ( 1 + cosx ) / ( 1 - cosx ) ( 1 + cosx )

=> (1 + cosx )/( 1 - cosx ) Rhs prooved ♻

________________________

Hope it helps you !!!

@Rajukumar111 (^^)


qqqqqqppppppqpqpqpqp: yup it helps me a lot
qqqqqqppppppqpqpqpqp: no sir me ty
qqqqqqppppppqpqpqpqp: yup
Answered by varun000
0
hope it helps you dear....
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