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area of each tile= 1/2 ×d1×d2
1/2×45×30 cm sq
15×45 cm sq
675 cm sq
675÷100×100 m sq
0.0675 m sq
hence, cost of 3000 tiles= 0.0675 ×3000
=67.5×3
=202.5
=202.5×4
=810
the total cost will be rupee 810
1/2×45×30 cm sq
15×45 cm sq
675 cm sq
675÷100×100 m sq
0.0675 m sq
hence, cost of 3000 tiles= 0.0675 ×3000
=67.5×3
=202.5
=202.5×4
=810
the total cost will be rupee 810
anshchakrabortp54gjx:
plzz mark my answer as brainliest: -)
Answered by
1
Hey
Your ans
Area of 3000 tiles = 1/2 product of diagonals
==>> 1 / 2 x 30 x 45 x 3000
==>> 15 x 45 x 3000
==>> 675 x 3000
==>> 2025000 cm sq
==>> 202.5 m sq
Total cost ===>> 4 x 202.5
=> Rs 810.0
I hope it will help you
Thanks
Your ans
Area of 3000 tiles = 1/2 product of diagonals
==>> 1 / 2 x 30 x 45 x 3000
==>> 15 x 45 x 3000
==>> 675 x 3000
==>> 2025000 cm sq
==>> 202.5 m sq
Total cost ===>> 4 x 202.5
=> Rs 810.0
I hope it will help you
Thanks
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