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distance of point lying on a circle to centre is eqaul to radius of the circle hence
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Point A(4,3) and B(x,5) are on same cirle with centre O(2,3)
OA = OB = Radius of circle
Distance b/w two points = √(y₂-y₁)² + (x₂-x₁)
OA = √(3-3)² + (2-4)² = √4
OB = √(3-5)² + (2-x)² = √4 + (2-x)²
As, OA = OB
⇒ √4 = √4 + (2-x)²
⇒ 4 = 4 + (2-x)²
⇒ 4-4 = (2-x)²
⇒ (2-x)² = 0
⇒ (2-x)(2-x) = 0
∴ 2-x = 0
⇒ x = 2
Therefore, the value of x is 2
OA = OB = Radius of circle
Distance b/w two points = √(y₂-y₁)² + (x₂-x₁)
OA = √(3-3)² + (2-4)² = √4
OB = √(3-5)² + (2-x)² = √4 + (2-x)²
As, OA = OB
⇒ √4 = √4 + (2-x)²
⇒ 4 = 4 + (2-x)²
⇒ 4-4 = (2-x)²
⇒ (2-x)² = 0
⇒ (2-x)(2-x) = 0
∴ 2-x = 0
⇒ x = 2
Therefore, the value of x is 2
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