Question

solve this question please

Answer 1

If p(x) = 2x² - 7x + 1, then evaluate p(3) + p(½) + p(-2).

Answer: -9

Step-by-step explanation:

Given: p(x) = 2x² - 7x + 1

To find: p(3) + p(½) + p(-2)

Putting value of x as 3:

p(3) = 2(3)² - 7(3) + 1

= 2 × 9 - 21 + 1

= 18 - 21 + 1

= -2

Putting value of x as ½ :

p(½) = 2(½)² - 7(½) + 1

= 2 × ¼ - 7/2 + 1

= 2/4 - 7/2 + 1

= 0.5 - 3.5 + 1

= -2

Putting value of x as (-2) :

p(-2) = 2(-2)² - 7(2) + 1

= 2 × 4 - 14 + 1

= 8 - 14 + 1

= -5

Thus,

p(3) = -2, p(½) = -2 and p(-2) = -5

.°. p(3) + p(½) + p(-2)

= (-2) + (-2) + (-5)

= - 4 - 5

= -9

Thus, If p(x) = 2x² - 7x + 1, then p(3) + p(½) + p(-2) = -9.

Answer 2

Given expression:

• p(x) = 2x² - 7x + 1

To evaluate:

• p(3) + p(½) + p(-2)

Solution:

• p(3) = 2(3)² - 7(3) + 1

→ P(3) = 2(9) - 7(3) + 1

→ P(3) = 18 - 21 + 1

→ P(3) = -2

• P(½) = 2(½)² - 7(½) + 1

→ P(½) = 2 × (1/4) - (7/2) + 1

→ P(½) = 1/2 - 7/2 + 1

→ P(½) = -2

• P(-2) = 2(-2)² - 7(-2) + 1

→ P(-2) = 2(4) - 7(2) + 1

→ P(-2) = 8 - 14 + 1

→ P(-2) = -5

__________________

Required value:

→ p(3) + p(½) + p(-2)

→ (-2) + (-2) + (-5)

→ - 2 - 2 - 5

→ -9

Hence, our required value is -9.