Question

solve this question please ​

Answer 1

Answer:

angle A and angle B =90°( from the theorom the tangent to the circle at any point is the perpendicular to the radius of the circle that passes through the point of contact”.)

hence

In quadrilateral AOBC,

A+O+B+x=360°

90+145+90+x=360°

325°+x=360°

x=35°