Question

solve this question please!

Answer 1

using compendo and divide do we get
$\frac{{x}^{3} + 12 {x}^{2} + 6x + 8}{ {x}^{3} + 12 {x}^{2} - 6x - 8} = \frac{ {y}^{3} + 27y + 9 {y}^{2} + 27}{ {y}^{3} + 27y - 9 {y}^{2} - 27}$
=>
$\frac{{(x + 2)}^{3} }{(x - 2) ^{3}} = \frac{{(y + 2)}^{3} }{ {(y - 2)}^{3} }$

=> on applying cube roots on both sides , we get
$\frac{x + 2}{x - 2} = \frac{y + 3}{y - 3}$
on applying componendo and dividendo, we get
$\frac{ x + 2 + x - 2 }{x + 2 - (x - 2)} = \frac{y + 3 + y - 3}{ y + 3 - (y - 3)}$
=>
2x/4 =2y/6 => x/y =4/6=2/3. hence x:y =2:3 . Hope it helps you... Mark me as Brainliest.