solve this question please!!!
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Hello.
Hope this helps.
Since the triangles have the same base BC, the ratio of their area is just the ratio of their heights from BC:
Area(PBC) / Area(ABC)
= ( distance of P from BC ) / ( distance of A from BC ).
So we need to find the distance from a point (x,y) to the line BC.
B = (-5, 3) and C = (2, -4)
The line BC is
( y - 3 ) / ( x + 5 ) = ( -4 - 3 ) / ( 2 + 5) = -1
=> y - 3 = -x - 5
=> x + y + 2 = 0.
The distance from a point (x,y) to the line BC is then
| x + y + 2 | / √(1² + 1²) = | x + y + 2 | / √2
Using this, the distance from A = (5, 1) to line BC is
| 5 + 1 + 2 | / √2 = 7 / √2
Therefore
Area(PBC) / Area(ABC)
= ( distance of P from BC ) / ( distance of A from BC )
= | x + y + 2 | / 7
sowmiya35:
answer us not explained properly
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