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find all the zero of 3x^3 + 16x^2 + 23x + 6 if two of its zeros are -3 and -2. please explain the question and give a step by step answer.
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Answer:
let,x+3=
x=-3
and x+2=0
x=-2
(x+3)(x+2)
x²+2x+3x+6
x(x+2)3(x+2)
(x+2)(x+3)
x+2=0. x+3=0
x=-2. x=-3
therefore the other zeros are -2,-3
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