Question

solve this question please help anyone​

Answer 1

SEE THE AATACHMENT YOUR ANSWER IS THIS AND I THINK IT IS CORRECT

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Answer 2

Answer:

∑k=111(2+3k)

∑k=1112+∑k=1113k

∑k=1112=2+2+2+...........(11times)

=2×11=22

∑k=1113k=3+32+33+........311

This series is a G.P. with first term= a=3, common ratio =r=323=3

and number of terms =n

We know that sum of n terms of a G.P=a.rn−1r−1

∴∑k=1113k=S11=3*(3¹¹−1)/(13−1)=32(3¹¹−1)

⇒∑k=111(2+3k)=22+32(3¹¹−1)