Math, asked by Manishpaul, 1 year ago

solve this question plz

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Answered by saindulakavath

refer the picture given above.

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Manishpaul: bhai yha c ko tum 0 mane ho kya?

saindulakavath: O letter nhi bhai..... zero

Manishpaul: ha ha whi puch rha hu,,yha c ka value zero let kiye ho

Manishpaul: ??

saindulakavath: qstn me c ka value ni diya.....so i considered c as 0

saindulakavath: aise likhne se faraq nai pdthi

Manishpaul: accha thanks bhai

saindulakavath: wlcm bro

Answered by rohitkumargupta

-------☺️☺️☺️ HELLO DEAR ☺️--------

5u²+10u

=> 5u²+10u +0 =0

a=5 =cooeficient of x²

b=10=cooeficient of x

c=0=cooeficient of x^0

-----------now Solve the Equation,-----------

5u²+10u+0=0

=> 5u²+10u+0u+0=0

=> 5u(u+2) +0(u+0)=0

=> u=0 or u= -2

we know that:-

$\alpha + \beta = \frac{ - b}{a} \\ = > \alpha + \beta = \frac{10}{5} = - 2$
and

$\alpha \times \beta = \frac{c}{a} \\ = > \alpha \times \beta = \frac{0}{5} = 0$
I HOPE ITS HELP YOU DEAR,
THANKS ☺️☺️☺️☺️☺️☺️☺️

rohitkumargupta: (:

rohitkumargupta: Mark as brainliest

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