Math, asked by kcanil610, 10 months ago

solve this question plz fast​

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Answered by Ahinush
0

Step-by-step explanation:

1 answer of this question because if the old are the cut to whether it will be solved

Answered by shadowsabers03
2

\dfrac {(p-q)^2-r^2}{p^2-(q+r)^2}+\dfrac {(q-r)^2-p^2}{q^2-(r+p)^2}+\dfrac {(r-p)^2-q^2}{r^2-(p+q)^2}\\\\\\=\dfrac {(p-q+r)(p-q-r)}{(p+q+r)(p-q-r)}+\dfrac {(q-r+p)(q-r-p)}{(q+r+p)(q-r-p)}+\dfrac {(r-p+q)(r-p-q)}{(r+p+q)(r-p-q)}\\\\\\=\dfrac {p-q+r}{p+q+r}+\dfrac {q-r+p}{q+r+p}+\dfrac {r-p+q}{r+p+q}\\\\\\=\dfrac {p-q+r+q-r+p+r-p+q}{p+q+r}\\\\\\=\dfrac {p+q+r}{p+q+r}\\\\\\=\mathbf {1}

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