Question

Solve this question

Prove that 0/0=2

Answer 1

0/0 =2

As x^2 - x^2 =0

$\implies\frac{x {}^{2} - x {}^{2} }{ {x}^{2} - x {}^{2} }$

Using identity a^2-b^2 = (a+b)(a-b)

and taking x common

$\implies{ \frac{(x + x)(x - x)}{ x(x - x) } }$


$\implies{ \frac{(x + x)( \cancel{x - x)}}{ x( \cancel{x - x})} }$


$\implies{ \frac{x + x}{x} }$



$\implies{ \frac{2x}{x} }$


$\implies{ \frac{2{ \cancel{x}}}{ \cancel{x}} }$


$\implies{2}$



$\boxed{ \bf{hence \: proved}}$

Answer 2

here is your answer

0/0 = (100-100)/(100-100)

= (10^2 - 10^2) / 10 (10-10)

= (10 + 10) × (10-10) / 10 (10-10)

(10-10) gets cancelled

then,

= (10+10)/10

= 20/10

= 2/1

= 2

0/0 = 2

so hence we can say that 0/0 = 2

i hope it helped uh