Question

solve this question right now...​

Answer 1

SOLUTION:-

Let the point P divide AB in the ratio k:1.

Then the coordinate of P are;

$= > P[\frac{k(4) + 1( - 3)}{k + 1} , \frac{k( - 9) + 1(5)}{k + 1} ]\\ \\ = > P [ \frac{4k - 3}{k + 1} , \frac{ - 9k + 5}{k + 1} ]$

So,

The coordinates of P are given as (2,-5)

Therefore,

$\frac{4k - 3}{k + 1} = 2 \: and \: \frac{ - 9k + 5}{k + 1} = - 5 \\ \\ = > 4k - 3 = 2k + 2 \: \: and \: \: - 9k + 5 = - 5k - 5 \\ \\ = > 4k - 2k = 2 + 3 \: \: and \: \: - 9k + 5k = - 5 - 5 \\ \\ = >2k = 5 \: \: and \: \: - 4k = - 10 \\ \\ = > k = \frac{5}{2} \: \: and \: \: k = \frac{10}{4} = \frac{5}{2}$

Hence,

The point P divides AB in the ratio 5:2.

Hope it helps ☺️

Answer 2

Answer:

plzzz give me brainliest ans and plzzzz follow me please