solve this question step by step please..... tommorrow is my math exam please
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1
Answer:
1/7
Step-by-step explanation:
A non-leap year has 365 days
A year has 52 weeks. Hence there will be 52 Sundays for sure.
52 weeks = 52 x 7 = 364 days .
365– 364 = 1day extra.
In a non-leap year there will be 52 Sundays and 1day will be left.
This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday,friday,Saturday, Sunday.
Of these total 7 outcomes, the favourable outcomes are 1.
Hence the probability of getting 53 sundays = 1 / 7
Randomboy123:
Mark as brainliest :)
Answered by
1
normally there are 52 weeks in a non leap year...so 1 day is left as 52×7=364
This day can be any day of the week...
P(E)=1/7
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