Math, asked by KingSrikar, 2 months ago

Solve THIS Question : \rm{y-(y-1)/7=1-(y-2)/5}

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Answered by ExploringMathematics
0

\rm{y-(y-1)/7=1-(y-2)/5}

\longrightarrow\rm{7y/7-(y-1)/7=5/5-(y-2)/5}

\longrightarrow\rm{(7y-(y-1))/7=(5-(y-2))/5}

\longrightarrow\rm{(7y-y+1)/7=(5-y+2)/5}

\longrightarrow\rm{(6y+1)/7=(7-y)/5}\longrightarrow\rm{5(6y+1)=7(7-y)}

\longrightarrow\rm{30y+5=49-7y}\longrightarrow\rm{30y+5-5=49-7y-5}

\longrightarrow\rm{30y=-7y+44}\longrightarrow\rm{30y+7y=-7y+44+7y}

\longrightarrow\rm{37y=44}\longrightarrow\rm{37y/37=44/37}\longrightarrow\rm{y=44/37}

Answered by Anonymous
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Answer:Answer:The alveoli are where the lungs and the blood exchange oxygen and carbon dioxide during the process of breathing in and breathing out. Oxygen breathed in from the air passes through the alveoli and into the blood and travels to the tissues throughout the body.

Answer:Answer:The alveoli are where the lungs and the blood exchange oxygen and carbon dioxide during the process of breathing in and breathing out. Oxygen breathed in from the air passes through the alveoli and into the blood and travels to the tissues throughout the body.

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