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this question is from class11 physics cbse board
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Answers
Thanks for asking the question!
SOLUTION::
As it is given in question ,
a vector = 4i +3j
b vector = 3i + 4j
(a) Magnitude of a vector , |a| = √(4² + 3²) = √25 = 5
(b) Magnitude of b vector , |b| = √(3²+4²) = √25 = 5
(c) Magnitude of a vector + b vector , |a+b| = |4i + 3j +3i + 4j| = |7i + 7j|
= √(7² + 7²)
= 7√2
(d) Magnitude of a vector - b vector,|a+b| = |( 4-3)i +(3-4)j| = 1i -1j
=√[1²+(-1)²]
= √2
All parts are solved.
Hope this helps you...
Explanation:
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