Question

solve this question
This question is of Trigonometry chapter​

Answer 1

Answer:

$\sin(a) = \frac{2}{3} = \frac{p}{h} \\ \\ base \: = \sqrt{5} \\ \cot(a) = \frac{ \sqrt{5} }{2} \\ \frac{ \sqrt{5} }{2} - 1 \\ = > \frac{ \sqrt{5 } - 2}{2}$

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Answer 2

Answer:

(√5-3)/3

Step-by-step explanation:

3 sinA =2

sinA =2/3= opposite side(a)/ hypotenuse (c)

considering as a right triangle

c^2=a^2+b^2

b^2=c^2- a^2

= 9-4=5

b=√5= adjacent side

now cotA = adjacent side/ opposite side

=√5/3

now, (cot A-1)= √5/3-1=(√5-3)/3