Question

Solve this question

Two filling pipes P and Q are fitted to a tank. P is
first opened for half the time taken by Q alone to
fill the tank and then closed. Q is then opened for
half the time taken by P alone to fill the tank. If the

tank is full after a total of 6 h after P was opened,
then for how long was Q opened? (in hours)

NO SPAM ​

Answer 1

(i) Let the time takenby P and Q to fill the tank invididually be x hours and y hours respectively and proceed. (ii) Let P takes x hours and Q takes y hours. (iii) Then P is opnend for y 2 y2 hours and Q for x 2 x2hours. (iv) Frame the equations and solve for y, i.e., x 2 + y 2 = 6 x2+y2=6 and y 2 x + x 2 y = 1 y2x+x2y=1.

PLZ MARK IT AS BRAINLIEST!

Answer 2

Step-by-step explanation:

let P alone take x hours and

Q alond take y hours to fill the tank.

ATQ, Q is opened for half the time taken by P

alone to fill the tank.

therefore time for which Q was opened=x/2

time for which P was opened=x/2

eq.

x/2+x/2=6

2x/2=6

x=6

now time for which Q was opened=x/2=6/2

=3hours

hope this helps you dear