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If both the resistors are in series then
Rs=R +R=9+9=18
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Explanation:
Here 10Ω is in parallel with 10Ω ∴ R across Pɸ = 10 + (10 || 10) = 10 + {(10 × 10) / (10 + 10)} = 15Ω hence it can be drawn as Here 15 Ω is parquet with 10Ω hence equivalent resistance is {(15 × 10)/(15 + 10)} = 6Ω Hence circuit reduces to RAB = 10 + [R || (10 + 6)] = 10 + [R || 16] given RAB = 18Ω ∴ 18 – 10 = R || 16 8 = {(R × 16)/(R + 16)} ∴ R + 16 = 2R 16 = R R = 16Ω.Read more on Sarthaks.com - https://www.sarthaks.com/346516/for-what-value-of-r-the-net-resistance-of-the-circuit-will-be-18-ohms
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