solve this question (y-1/2) (y+3/8)
Answers
Answered by
0
(y-1/2)(y+3/8)=(2y-1)(8y+5)=16y^2-2y-3
Rithvika20:
(y-1/2)(y+3/8)
Answered by
8
(Y-1÷2) (Y+3÷8)
= (8Y-8) (2Y+6)
= 16Y2+48Y-16Y-48
=16Y2+32Y-48
It is your correct answer.
Please, give me thank you.
Please, mark me brainlist.
= (8Y-8) (2Y+6)
= 16Y2+48Y-16Y-48
=16Y2+32Y-48
It is your correct answer.
Please, give me thank you.
Please, mark me brainlist.
y(y-1/2)+3/8(y-1/2)
y2-1/2y+3/8y-3/16
y2-7y/8-3/16=0
16y2-14y-3=16*0 [take lcm]
16y2-8y-6y-3=0
8y(2y-1)-3(2y-1)=0
(2y-1)(8y-3)=0
y=1/2 or y=3/8
i guess this is the correct answer
y2-1/2y+3/8y-3/16
y2-7y/8-3/16=0
16y2-14y-3=16*0 [take lcm]
16y2-8y-6y-3=0
8y(2y-1)-3(2y-1)=0
(2y-1)(8y-3)=0
y=1/2 or y=3/8
i guess this is the correct answer
you have to do this by the identity
Similar questions