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we know the multiplication of the roots is equal to : c/a
so: (1+β/α)(1+α/β)=1+α/β+β/α+1=2+ (α^2 + β^2)/αβ = 2+ [(α+β)^2 -2αβ]/αβ =M
since αβ=c/a=3/1=3 & α+β=-b/a =-4/1=-4 THEN M=2+[(-4)^2 -2(3)]/3=16/3
we know that the sum of the roots is equal to : -b/a
so : (1+β/α)+(1+α/β)=M=16/3
SO: 3x^2 -16x+16
so: (1+β/α)(1+α/β)=1+α/β+β/α+1=2+ (α^2 + β^2)/αβ = 2+ [(α+β)^2 -2αβ]/αβ =M
since αβ=c/a=3/1=3 & α+β=-b/a =-4/1=-4 THEN M=2+[(-4)^2 -2(3)]/3=16/3
we know that the sum of the roots is equal to : -b/a
so : (1+β/α)+(1+α/β)=M=16/3
SO: 3x^2 -16x+16
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