solve this questions given in the picture
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angle5=90°(angle sum property of triangleABC)
angle1+angle5 = 180°(linear pair)
angle1=180-90
angle1=90°
angle1+angle5 = 180°(linear pair)
angle1=180-90
angle1=90°
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Hlww dear......
Here is ur answeR .....
1) We know,
<BAD= <CAE (Vertically opp. angles)
so, <5= 110°
<5+<2=180° (Linear pair)
<2= 180-110= 70°
<2= <4 = 70° (vertical opposite angles)
In TriangleABC,
<ABC+ <BCA+<BAC= 180° (angle sum property)
<3+ 30°+70°=180°
<3= 180-100=> 80°
Similarly,
In trIangleAED,
<2+<1+60°= 180° (Angle sum property)
70°+60°+<1=180°
<1= 180-130 => 50°
Here is ur answeR .....
1) We know,
<BAD= <CAE (Vertically opp. angles)
so, <5= 110°
<5+<2=180° (Linear pair)
<2= 180-110= 70°
<2= <4 = 70° (vertical opposite angles)
In TriangleABC,
<ABC+ <BCA+<BAC= 180° (angle sum property)
<3+ 30°+70°=180°
<3= 180-100=> 80°
Similarly,
In trIangleAED,
<2+<1+60°= 180° (Angle sum property)
70°+60°+<1=180°
<1= 180-130 => 50°
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