Math, asked by khanjibashirgmailcom, 1 year ago

solve this quetion i will mark as brainleist

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Answers

Answered by myidentity
1

Answer:

Step-by-step explanation:

Answer.

Given units digit is x and tens digit is y

Hence the two digit number = 10y + x

Number obtained by reversing the digits = 10x + y

Given that sum of a two digit number and the number obtained by reversing the order of its digits is 121.

Hence (10y + x) + (10x + y) = 121

⇒ 11x + 11y = 121

∴ x + y = 11

Thus the required linear equation is x + y = 11.

Hope this answers your question

Please mark as brainliest :)

Answered by Ashishrajput1306
1

Answer:

Step-by-step explanation:

Let,

Tens digit be x.

And unit digit be y.

So,number be 10x+y.

No. Obtain by reversing be 10y+x.

A.T.Q

10x+y+10y+x=121

11x+11y=121

11(x+y)=11×11

x+y=11...eqn 1.

From next part of question.

y=x+7

x-y=-7.....eqn 2

From eqn 1+eqn 2

x+y+x-y=11-7

2x=4.

x=2.

Putting x=2 in eqn 1.

x+y=11.

2+y=11

y=11-2.

y=9.

So, no.(10x+y) =10×2+9=29.

Hence, no. be 29.

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