Question

solve this simultaneous equation: 1/3x+y=10/3;2x+1/4y=11/4

Answer 1

Hello Dear.

Let the equation
   (1/3)x + y = 10/3 -------------------------eq(i)
& 2x + (1/4)y = 11/4 -----------------------eq(ii)

From eq(i),
 (x + 3y)/3 = 10/3
⇒ x + 3y = 10
⇒ x = 10 - 3y

From eq(ii),
(8x + y)/4 = 11/4
⇒ 8x + y = 11 -------------------------eq(iii)


Now,Putting the value of x in eq(iii),
8(10 - 3y) + y = 11
⇒ 80 - 24y + y = 11
⇒ 80 - 23y = 11
⇒ 23y = 80 - 11
⇒ 23y = 69
∴  y =  3

Now, Putting Value of the y = 3 in eq(iii),
  8x + 3 = 11
⇒ 8x = 11 - 3
⇒ 8x = 8
∴ x = 1


Hence, the value of the x and y is 1 and 3 respectively.


Hope it helps.

Answer 2

It's correct answer

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