Question

solve this solve this​

Answer 1

2x⁴−3x³−3x²+6x−2 = 0

2x⁴−2x³−x³+x²−4x²+4x+2x−2 = 0

(2x³−x²−4x+2)(x−1) = 0

(x−1)(x²−2)(2x−1) = 0

(x−1)(2x−1)(x−√2)(x+√2) = 0

Therefore, all the roots are

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x₁,₂,₃,₄ = 1, ½ , √2 , –√2

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