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Since the arcs AC and BD are equal,
⟨ABC = ⟨BAD ...(1)
because the arcs of equal length subtend equal angles on the circle, or at the center of the circle.
But, in ∆ABD and ∆BED,
⟨ADB = ⟨BED = 90°
(⟨ADB is the angle subtended by the diameter on the circle; DE is perpendicular to AB.)
⟨DBA = ⟨DBE (common angle)
Therefore,
⟨BDE = ⟨BAD ...(2)
From (1) and (2),
⟨ABC = ⟨BDE
Hence Proved!
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