Question

Solve this sum 12÷3+4×3÷4÷5+3×3÷4=?

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Answer 1

Answer:

12 ÷ 3 + 4 × 3 ÷ 4 ÷ 5 + 3 × 3 ÷ 4

= 4 + 4 × 0.75 ÷ 5 + 3 × 0.75

= 4 + 4 × 0.15 + 2.25

= 4 + 0.6 + 2.25

= 6.85

Answer 2

Answer:

• (i) 2 – 3/5 = 2/1 – 3/5
• (i) 2 – 3/5 = 2/1 – 3/5 = (2 * 5 – 3 * 1)/5 [LCM (1, 5) = 5]
• (i) 2 – 3/5 = 2/1 – 3/5 = (2 * 5 – 3 * 1)/5 [LCM (1, 5) = 5] = (10 - 3)/5
• (i) 2 – 3/5 = 2/1 – 3/5 = (2 * 5 – 3 * 1)/5 [LCM (1, 5) = 5] = (10 - 3)/5 = 7/5
• (i) 2 – 3/5 = 2/1 – 3/5 = (2 * 5 – 3 * 1)/5 [LCM (1, 5) = 5] = (10 - 3)/5 = 7/5 = 1
• (i) 2 – 3/5 = 2/1 – 3/5 = (2 * 5 – 3 * 1)/5 [LCM (1, 5) = 5] = (10 - 3)/5 = 7/5 = 1 (ii) 4 + 7/8 = 4/1 + 7/8
• (i) 2 – 3/5 = 2/1 – 3/5 = (2 * 5 – 3 * 1)/5 [LCM (1, 5) = 5] = (10 - 3)/5 = 7/5 = 1 (ii) 4 + 7/8 = 4/1 + 7/8 = (4 * 8 + 7)/8 [LCM (1, 8) = 8]
• (i) 2 – 3/5 = 2/1 – 3/5 = (2 * 5 – 3 * 1)/5 [LCM (1, 5) = 5] = (10 - 3)/5 = 7/5 = 1 (ii) 4 + 7/8 = 4/1 + 7/8 = (4 * 8 + 7)/8 [LCM (1, 8) = 8] = (32 + 7)/8
• (i) 2 – 3/5 = 2/1 – 3/5 = (2 * 5 – 3 * 1)/5 [LCM (1, 5) = 5] = (10 - 3)/5 = 7/5 = 1 (ii) 4 + 7/8 = 4/1 + 7/8 = (4 * 8 + 7)/8 [LCM (1, 8) = 8] = (32 + 7)/8 = 39/8
• (i) 2 – 3/5 = 2/1 – 3/5 = (2 * 5 – 3 * 1)/5 [LCM (1, 5) = 5] = (10 - 3)/5 = 7/5 = 1 (ii) 4 + 7/8 = 4/1 + 7/8 = (4 * 8 + 7)/8 [LCM (1, 8) = 8] = (32 + 7)/8 = 39/8 = 4
• (i) 2 – 3/5 = 2/1 – 3/5 = (2 * 5 – 3 * 1)/5 [LCM (1, 5) = 5] = (10 - 3)/5 = 7/5 = 1 (ii) 4 + 7/8 = 4/1 + 7/8 = (4 * 8 + 7)/8 [LCM (1, 8) = 8] = (32 + 7)/8 = 39/8 = 4 (iii) 3/5 + 2/7 = (3 * 7 + 2 * 5)/35 [LCM (7, 5) = 35]
• (i) 2 – 3/5 = 2/1 – 3/5 = (2 * 5 – 3 * 1)/5 [LCM (1, 5) = 5] = (10 - 3)/5 = 7/5 = 1 (ii) 4 + 7/8 = 4/1 + 7/8 = (4 * 8 + 7)/8 [LCM (1, 8) = 8] = (32 + 7)/8 = 39/8 = 4 (iii) 3/5 + 2/7 = (3 * 7 + 2 * 5)/35 [LCM (7, 5) = 35] = (21 + 10)/35
• (i) 2 – 3/5 = 2/1 – 3/5 = (2 * 5 – 3 * 1)/5 [LCM (1, 5) = 5] = (10 - 3)/5 = 7/5 = 1 (ii) 4 + 7/8 = 4/1 + 7/8 = (4 * 8 + 7)/8 [LCM (1, 8) = 8] = (32 + 7)/8 = 39/8 = 4 (iii) 3/5 + 2/7 = (3 * 7 + 2 * 5)/35 [LCM (7, 5) = 35] = (21 + 10)/35 = 31/35
• (i) 2 – 3/5 = 2/1 – 3/5 = (2 * 5 – 3 * 1)/5 [LCM (1, 5) = 5] = (10 - 3)/5 = 7/5 = 1 (ii) 4 + 7/8 = 4/1 + 7/8 = (4 * 8 + 7)/8 [LCM (1, 8) = 8] = (32 + 7)/8 = 39/8 = 4 (iii) 3/5 + 2/7 = (3 * 7 + 2 * 5)/35 [LCM (7, 5) = 35] = (21 + 10)/35 = 31/35(iv) 9/11 – 4/15 = (9 * 15 – 4 * 11)/165 [LCM (11, 15) = 165]
• (i) 2 – 3/5 = 2/1 – 3/5 = (2 * 5 – 3 * 1)/5 [LCM (1, 5) = 5] = (10 - 3)/5 = 7/5 = 1 (ii) 4 + 7/8 = 4/1 + 7/8 = (4 * 8 + 7)/8 [LCM (1, 8) = 8] = (32 + 7)/8 = 39/8 = 4 (iii) 3/5 + 2/7 = (3 * 7 + 2 * 5)/35 [LCM (7, 5) = 35] = (21 + 10)/35 = 31/35(iv) 9/11 – 4/15 = (9 * 15 – 4 * 11)/165 [LCM (11, 15) = 165] = (135 - 44)/165
• (i) 2 – 3/5 = 2/1 – 3/5 = (2 * 5 – 3 * 1)/5 [LCM (1, 5) = 5] = (10 - 3)/5 = 7/5 = 1 (ii) 4 + 7/8 = 4/1 + 7/8 = (4 * 8 + 7)/8 [LCM (1, 8) = 8] = (32 + 7)/8 = 39/8 = 4 (iii) 3/5 + 2/7 = (3 * 7 + 2 * 5)/35 [LCM (7, 5) = 35] = (21 + 10)/35 = 31/35(iv) 9/11 – 4/15 = (9 * 15 – 4 * 11)/165 [LCM (11, 15) = 165] = (135 - 44)/165 = 91/165
• (i) 2 – 3/5 = 2/1 – 3/5 = (2 * 5 – 3 * 1)/5 [LCM (1, 5) = 5] = (10 - 3)/5 = 7/5 = 1 (ii) 4 + 7/8 = 4/1 + 7/8 = (4 * 8 + 7)/8 [LCM (1, 8) = 8] = (32 + 7)/8 = 39/8 = 4 (iii) 3/5 + 2/7 = (3 * 7 + 2 * 5)/35 [LCM (7, 5) = 35] = (21 + 10)/35 = 31/35(iv) 9/11 – 4/15 = (9 * 15 – 4 * 11)/165 [LCM (11, 15) = 165] = (135 - 44)/165 = 91/165(v) 7/10 + 2/5 + 3/2 = (7 * 1 + 2 * 2 + 3 * 5)/10
• (i) 2 – 3/5 = 2/1 – 3/5 = (2 * 5 – 3 * 1)/5 [LCM (1, 5) = 5] = (10 - 3)/5 = 7/5 = 1 (ii) 4 + 7/8 = 4/1 + 7/8 = (4 * 8 + 7)/8 [LCM (1, 8) = 8] = (32 + 7)/8 = 39/8 = 4 (iii) 3/5 + 2/7 = (3 * 7 + 2 * 5)/35 [LCM (7, 5) = 35] = (21 + 10)/35 = 31/35(iv) 9/11 – 4/15 = (9 * 15 – 4 * 11)/165 [LCM (11, 15) = 165] = (135 - 44)/165 = 91/165(v) 7/10 + 2/5 + 3/2 = (7 * 1 + 2 * 2 + 3 * 5)/10 = (7 + 4 + 15)/10
• (i) 2 – 3/5 = 2/1 – 3/5 = (2 * 5 – 3 * 1)/5 [LCM (1, 5) = 5] = (10 - 3)/5 = 7/5 = 1 (ii) 4 + 7/8 = 4/1 + 7/8 = (4 * 8 + 7)/8 [LCM (1, 8) = 8] = (32 + 7)/8 = 39/8 = 4 (iii) 3/5 + 2/7 = (3 * 7 + 2 * 5)/35 [LCM (7, 5) = 35] = (21 + 10)/35 = 31/35(iv) 9/11 – 4/15 = (9 * 15 – 4 * 11)/165 [LCM (11, 15) = 165] = (135 - 44)/165 = 91/165(v) 7/10 + 2/5 + 3/2 = (7 * 1 + 2 * 2 + 3 * 5)/10 = (7 + 4 + 15)/10 = 26/10 op

Step-by-step explanation:

Answer: Conditions necessary for the transfer of heat from one body to the other through conduction are as follows: The two objects must be in contact with each other. The temperatures of both the objects must be different.