Question

The sum of the squares of two consecutive multipales of 6 is 1476,find the multiples?

(a) 12,18 (b) 24,30 (c) 36, 42 (d) 6,12
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Answer 1

Answer:

88,56

Step-by-step explanation:

88,56 your questions

Answer 2

let the no is 6x and 6(x+1) .

now , according to question ,

=> (6x)² + ( 6x+6 )² = 1476

=> 36 { x²+ (x+1)²} =1476

=> x² + x²+2x +1 = 41

=>2x² + 2x -40 = 0

=>2( x² + x -20) = 0

=> 2(x+5)(x-4)= 0

so ,x is 4 and -5 .

here negative number is not possible , therefore x is 4 .

Hence , 6x = 24 and 6(x+1) = 30