solve this sum
expand:
(2a+3b+5) (2a-3b+5)
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fine
Answers
Answered by
12
(2a+3b+5) (2a-3b+5)
[ (a+b)(a-b) = a²-b² ]
= (2a)² - (3b+5)²
= 4a² -(9b² + 25 + 30b)
= 4a² -9b²-25 -30b
[ (a+b)(a-b) = a²-b² ]
= (2a)² - (3b+5)²
= 4a² -(9b² + 25 + 30b)
= 4a² -9b²-25 -30b
Answered by
7
(2a+3b+5)(2a-3b+5)
=4a^2-6ab +10a+6ab-9b^2+15b+10a-15b+25
=4a^2+20a-9b^2+25
=4a^2-6ab +10a+6ab-9b^2+15b+10a-15b+25
=4a^2+20a-9b^2+25
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