Math, asked by nabiluddin396, 1 year ago

Solve this sum. I need this quickly

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Answered by replyr
1
answer in the picture
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replyr: thanks
nabiluddin396: You didn't write the final result
Answered by MadiSheetal
1
Taking out a minus from the denominators of all,it will
[-(y+z)/(x-y)(z-x)]+[-(z+x)/(y-z)(x-y)]+[-(x+y)/(z-x)(y-z)]
The LCM is (x-y)(y-z)(z-x)
So then ,a minus is common.
Then,-[(y-z)(y+z)+(z-x)(z+x)+(x-y)(x+y)]÷(x-y)(y-z)(z-x)
-[y^2-z^2+z^2-x^2+x^2-y^2]÷same as above
=0/same=0


Omg,it was very difficult to write.. ok ,any ways ,if u feel any problem u can ask
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