Question

solve this suM problem

Answer 1

Step-by-step explanation:

1a and a are the same things

Answer 2

$\huge\bold{\mathtt{Question⇒}}$

Solve: $(a²+7a+12)÷(a+4)$

$\huge\bold{\mathtt{To\:find⇒}}$

The quotient.

$\huge\bold{\mathtt{Solution⇒}}$

Division⇒

$a+4\:)\:{\cancel{a²}}+7a+12\:(\:a+3$

$\:\:\:\:\:\:\:\:\:\:\:\:\:{\underline{\:{\cancel{a²}}+4a\:\:\:\:\:\:\:\:\:\:\:}}$

$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{\cancel{3a+12}}$

$\:\:\:\:\:\:\:\:\:\:\:\:\:{\underline{\:\:\:\:\:\:\:\:\:\:{\cancel{3a+12}}\:\:}}$

$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:0$

$\huge\bold{\mathtt{Hence⇒}}$

$(a²+7a+12)÷(a+4) = (a+3)$

$\huge\bold{\mathtt{Therefore⇒}}$

$(a²+7a+12)$ when divided by $(a+4)$ gives $(a+3).$

$\huge\bold{\mathtt{Done}}$

$\large\bold{\mathtt{Hope\:this\:helps\:you.}}$

$\large\bold{\mathtt{Have\:a\:nice\:day.}}$